Write a function that will return true
if the sum of all the numbers in odd positions
is the same as the sum of all the numbers in
even positions in a vector.

e.g., sumEvenOdd([1 2 3 4]) ==> 0 (false) because 1 + 3 != 2 + 4 


 sumEvenOdd([1 2 2 1]) ==> 1 (true) because 1 + 2 != 2 + 1 

 sumEvenOdd([1 1 2 2 3 3 4 5 5 4 ]) ==> 1 (true) because  

                      1 + 2 + 3 + 4 + 5 = 1 + 2 + 3 + 5 + 4